id.' ORDER BY rang LIMIT 1') or die("Anfrage nicht erfolgreich"); $image = ''; while($obj2 = mysql_fetch_object($query2)) { $image = $obj2->file_name; } $sql = " UPDATE items SET default_image_file_name='".$image."' WHERE id=".$obj->id." "; echo "
".$sql; mysql_query($sql); } ?>